Question

AB is a diameter of the circle APBR, as shown in the figure. APQ and RBQ are straight lines. Find : ∠BPR

Answer 1

∠ABP = 90° – ∠BAP

= 90° – 35°

= 55°

∴ ∠ABR = ∠PBR – ∠ABP

= 115° – 55°

= 60°

∴ ∠APR = ∠ABR = 60°

(Angles subtended by the same chord on the circle are equal)

∴ ∠BPR = 90° – ∠APR

= 90° – 60°

= 30°