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Question
AB is a chord of circle with centre O and radius 4cm. AB is length of 4cm. Find the area of sector of the circle formed by chord AB
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Solution
AB is chord AB = 4cm
OA = OB = 4cm
OAB is equilateral triangle ∠AOB = 60°
Area of sector (formed by chord [shaded region]) = (area of sector)
`=theta/360^@× pir^2 =60/360× pi × 4 × 4 =(8pi)/3 cm^2`
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