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Question
A work of 25 J and 30 J is done when 5 C charge is moved first to point A and then to point B from infinity. Calculate the potential difference between points A and B.
Sum
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Solution 1
WA = 25 J
WB = 30 J, charge = Q = 5 C
Potential at point A = V1 = `"W"_"A"/"Q"`
V1 = `25/5 = 5` volt
Potential at point B = V2 = `"W"_"B"/"Q"`
V2 = `30/5 = 6` volt
Potential difference A and B = V = V2 − V1
V = 6 − 5 = 1 volt
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Solution 2
WA = 25 J
WB = 30 J, charge = Q = 5 C
Potential at point A = V1 = `"W"_"A"/"Q"`
V1 = `25/5 = 5` volt
Potential at point B = V2 = `"W"_"B"/"Q"`
V2 = `30/5 = 6` volt
Potential difference A and B = V = V2 − V1
V = 6 − 5 = 1 volt
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