Advertisements
Advertisements
Question
A vernier has 10 divisions and they are equal to 9 divisions of the main scale in length. If the main scale is calibrated in mm, what is its least count?
Advertisements
Solution
Value of 1 m.s.d. = 1 mm
10 vernier divisions = 9 m.s.d.
L.C. = Value of 1 m.s.d./number of divisions on vernier scale
= 1 mm/10
= 0.1 mm or 0.01 cm
APPEARS IN
RELATED QUESTIONS
The main scale of a vernier callipers is calibrated in mm and 19 divisions of main scale are equal in length to 20 divisions of the vernier scale. In measuring the diameter of a cylinder by this instrument, the main scale reads 35 divisions and 4th division of vernier scale coincides with a main scale division. Find
(i) Least count and (ii) Radius of a cylinder.
What do you understand by amplitude of simple pendulum?
How does the time period (T) of a simple pendulum depend on its length (l)? Draw a graph showing the variation of T2 with l. How will you use this graph to determine the value of g (acceleration due to gravity)?
Name the convenient unit you will use to measure:
length of a hall
Amongst the unit of volume which is most suitable for measuring:
Volume of a glass filled with milk
Amongst the unit of volume which is most suitable for measuring:
Volume of an exercise book
Amongst the unit of volume which is most suitable for measuring:
Volume of air in the room
The size of bacteria is 2 μ.. Find the number of bacteria in 3 m length.
