Advertisements
Advertisements
Question
A uniform metre rule of weight 10gf is pivoted at its 0 mark.
What moment of force depresses the rule?
Advertisements
Solution
Anticlockwise moment = 10 gf x 50 cm = 500 gf cm
RELATED QUESTIONS
The hand flour grinder is provided with a handle near the rim.
Sleepers are used below the rails.
What are contact forces? Give two Example
State one factor on which the magnitude of a non-contact force depends. How does it depend on the factor stated by you?.
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
The S.I. unit of moment of force is ______.
Give any two effects of a force on a non-rigid body.
Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
