Question

A uniform electric field of 10 N C⁻¹ exists in the vertically downward direction. Find the increase in the electric potential as one goes up through a height of 50 cm.

Answer 1

Electric field intensity, E = 10 N/C,
Change in height, ds = 50 cm =  `1/2`m 

Change in electric potential, dV = E.ds = 10 × `1/2= 5` V