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A Transformer Lowers E.M.F. from 220 V to 15 V. If 400 W Power is Given in Primary, Calculate (I) the Current in Primary Coil and (Ii) the Current in Secondary Coil.

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Question

A transformer lowers e.m.f. from 220 V to 15 V. If 400 W power is given in primary, calculate (i) the current in primary coil and (ii) the current in secondary coil.

Short/Brief Note
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Solution

(i) We know that Power = Ip × Ep 

or 400 = Ip × 220

∴ Ip = 1.8 A

(ii) Using  Ip × Ep = Is × Es 

∴ `"I"_"s" = ("I"_"p" xx "E"_"p")/"E"_"s"`

`"I"_"s" = (1.8 xx 220)/15`

= 26.4 A.

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