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A tea merchant blends two varieties of tea in the ratio of 5 : 4. The cost of first variety is ₹ 200 per kg and that of second variety is ₹ 300 per kg. - Mathematics

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Question

A tea merchant blends two varieties of tea in the ratio of 5 : 4. The cost of first variety is ₹ 200 per kg and that of second variety is ₹ 300 per kg. If he sells the blended tea at the rate of ₹ 275 per kg, find out the percentage of her profit or loss.

Sum
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Solution

Let quantity of first variety and second variety of tea be 5x kg and 4x kg respectively.

Cost of first variety of tea = ₹ (200 × 5x) = ₹ 1000x

Cost of second variety of tea = ₹ (300 × 4x) = ₹ 1200x

Total cost price of tea = ₹ (1000x + 1200x) = ₹ 2200x

Selling price of tea = ₹ (9x × 275) = ₹ 2475x

Here, S.P. > C.P.

Therefore, there is a profit of = ₹ (2475x – 2200x) = ₹ 275x

Profit % = `"Profit"/"C.P." xx 100 = (275x)/(2200x) xx 100` = 12.5%

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Chapter 7: Comparing Quantities - Exercise [Page 212]

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NCERT Exemplar Mathematics [English] Class 7
Chapter 7 Comparing Quantities
Exercise | Q 122. | Page 212

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