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Question
A student scored a total of 32 marks in class tests in Mathematics and Science. Had he scored 2 marks less in Science and 4 marks more in Mathematics, the product of his marks would have been 253. Find his marks in the two subjects.
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Solution
Given: Let Mathematics = M and Science = S. We are told: M + S = 32 and (M + 4)(S – 2) = 253.
Step-wise calculation:
1. From M + S = 32, we have S = 32 – M.
2. Substitute into the product equation:
(M + 4)(S – 2) = (M + 4)(32 – M – 2)
= (M + 4)(30 – M)
= 253
3. Expand: (M + 4)(30 – M) = –M2 + 26M + 120
So –M2 + 26M + 120 = 253.
4. Rearrange: –M2 + 26M + 120 – 253 = 0
⇒ –M2 + 26M – 133 = 0
Multiply by –1: M2 – 26M + 133 = 0
5. Solve quadratic:
Discriminant D = 262 – 4 × 133
= 676 – 532
= 144, `sqrt(D) = 12`
So `M = (26 ± 12)/2`
⇒ M = 19 or M = 7
6. Find S for each:
If M = 19, S = 32 – 19 = 13.
Check: (19 + 4)(13 – 2)
= 23 × 11
= 253
If M = 7, S = 32 – 7 = 25.
Check: (7 + 4)(25 – 2)
= 11 × 23
= 253
The student’s marks are either Mathematics = 19 and Science = 13 or Mathematics = 7 and Science = 25.
