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A string 1m long is fixed at one end. The other end is moved up and down with frequency of 15 Hz.

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Question

A string 1m long is fixed at one end. The other end is moved up and down with frequency of 15 Hz. Due to this, a stationary wave with four complete loops gets produced on the string. Find the speed of the progressive wave which produces the stationary wave.
[Hint: Remember that the moving end is an antinode.]

Sum
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Solution

Data: L = 1 m, n = 15 Hz.

Only one end of the string is fixed. As a result, at the free end, an antinode will form. Hence, with four and a half loops on the string, the string length is

L = `λ/4+4(λ/2)=9/4λ`

∴ λ = `("4L")/9=4/9xx1=4/9`m

v = n λ

∴ Speed of the progressive wave

v = `15xx4/9=60/9` = 6.667 m/s

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Chapter 6: Superposition of Waves - Exercises [Page 157]

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Balbharati Physics [English] Standard 12 Maharashtra State Board
Chapter 6 Superposition of Waves
Exercises | Q 19 | Page 157

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