Advertisements
Advertisements
Question
A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 6 N. Draw a diagram to show the application of forces and calculate the moment of forces applied.
Advertisements
Solution
Diameter of steering wheel = 0.5 m
Radius = `"d"/2`
= `0.5/2`
= 0.25 m
Magnitude of force = 6 N
Moment of couple = 6N × 0.5 m
= 3 N m
APPEARS IN
RELATED QUESTIONS
How does the magnitude of this non-contact force on the two bodies depend on the distance of separation between them?
In a door, handle is provided ......... from the hinges.
Name and define the S.I. and C.G.S. units of force. How are they related?
A body X of mass 5 kg is moving with velocity 20 m s-2 while another body Y of mass 20 kg is moving with velocity 5 m S-1. Compare the momentum of the two bodies.
It is easier to turn the steering wheel of a large diameter than that of a small diameter. Given reason.
Classify the following amongst contact and non-contact forces.
gravitation force
A wheel of diameter 3 m is shown in fig. 2 with axle at 0. A force F = 8 N is applied at Q in the direction shown in figure. Calculate the moment of force about:
(i) centre o, and
(ii) point p.
A jack screw is provided with a long arm. Explain why?
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.
A metal rod AB of length 80 cm is balanced at 45 cm from the end A with 100 gf weights suspended from the two ends.
- If this rod is cut at the center, C, then compare the weight of AC to the weight of BC. (Use >, < or =)
- Give a reason for your answer in (a).
