Advertisements
Advertisements
Question
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.
Options
5 N
10 N
20 N
0.2 N
Advertisements
Solution
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is 5 N.
Explanation:
`"Force" = "Moment of force"/"Length of lever"`
= `1/0.2`
= 5 N
APPEARS IN
RELATED QUESTIONS
Where can a body execute free vibrations?
A half metre rod is pivoted at the centre with two weights of 20gf and 12gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.

1) Which of the two forces acting on the rigid rod causes clockwise moment?
2) Is the rod in equilibrium?
3) The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
Moment of force =............... × distance of force from the point of turning.
In a door, handle is provided ......... from the hinges.
State the S.I. unit of moment of force.
In Fig. a force F is applied in a direction passing through the pivoted point O of the body. Will the body rotate? Give reason to support your answer.

Define the moment of force.
One joule is the amount of work done when a force of ......... moves a body through a distance of .......
Write the expression for the moment of force about a given axis.
Two similar vehicles are moving with the same velocity on the road, such that one of thus is loaded and the other one is empty which of the two vehicles will require larger force to stop?
