Advertisements
Advertisements
प्रश्न
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is ______.
विकल्प
5 N
10 N
20 N
0.2 N
Advertisements
उत्तर
A door lock is opened by turning the lever (handle) of length 0.2 m. If the moment of force produced is 1 Nm, then the minimum force required is 5 N.
Explanation:
`"Force" = "Moment of force"/"Length of lever"`
= `1/0.2`
= 5 N
APPEARS IN
संबंधित प्रश्न
How does the magnitude of this non-contact force on the two bodies depend on the distance of separation between them?
Moment of force =............... × distance of force from the point of turning.
Write the expression for the moment of force about a given axis of rotation.
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
State one way to obtain greater moment of a given force about a given axis of rotation.
Name of S.I. unit of the rate of change in momentum.
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m

Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
A wheel of diameter 3 m is shown in fig. 2 with axle at 0. A force F = 8 N is applied at Q in the direction shown in figure. Calculate the moment of force about:
(i) centre o, and
(ii) point p.

State two factors affecting the turning effect of a force.
The diagram in Fig shows two forces F1 = 5 N and F2 = 3 N acting at points A and B respectively of a rod pivoted at a point O, such that OA = 2 m and OB = 4 m.

Calculate:
- the moment of force F1 about O.
- the moment of force F2 about O.
- total moment of the two forces about O.
