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Question
A speaks truth in 75% cases and B in 80% of the cases. In v1hat percentage of cases are they likely to contradict each other. narrating the same incident?
Options
5%
15%
35%
45%
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Solution
35%
Explanation:
A Speak truth 75% i.e. P(A) =`3/4` `"P"(overline ("A")) =1/4`
Similarly 80% i.e. `"P"("B") =4/5 "P"(overline ("B") )=1/5`
While contradicting the narration
Probability =`"P"("A") ="P" (overline("B"))+"P"(overline("A"))"PB"`
`=3/4xx1/5+1/4xx4/5=7/20` or `7/20xx100=35%`
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