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Karnataka Board PUCPUC Science Class 11

A Source Emits 45 Joules of Energy in 15 S. What is the Radiant Flux of the Source? - Physics

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Question

A source emits 45 joules of energy in 15 s. What is the radiant flux of the source?

Sum
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Solution

Given,

Total energy emitted (E) = 45 J

Time (t) = 15 s

Radiant flux of the source is given by,

`"Radiant Flux"="Total energy emitted"/"Time"`

`=45/15=3"W"`

So, the radiant flux of the source is 3 W.

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Light Process and Photometry
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Chapter 22: Photometry - Exercise [Page 455]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 22 Photometry
Exercise | Q 1 | Page 455

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