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Karnataka Board PUCPUC Science Class 11

A Source Emits 31.4 W of Radiant Flux Distributed Uniformly in All Directions. the Luminous Efficiency is 60 Lumen Watt−1. What is the Luminous Intensity of the Source?

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Question

A source emits 31.4 W of radiant flux distributed uniformly in all directions. The luminous efficiency is 60 lumen watt−1. What is the luminous intensity of the source?

Sum
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Solution

Given that,

Radiant flux = 31.4 W

Since the radiant flux is distributed uniformly in all directions, the solid angle will be 4π Luminous efficiency = 60 lumen/W

So, luminous flux = luminous efficiency × radiant flux

= 60 × 31.4 lumen

Luminous intensity = `"Luminous flux"/"Solid angle"="Luminous flux"/(4pi)`

`=(60xx(31.4))/(4pi)`

= 150 candela

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Light Process and Photometry
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Chapter 22: Photometry - Exercise [Page 455]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 22 Photometry
Exercise | Q 8 | Page 455
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