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Question
A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s, find the frequency.
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Solution
Distance between two successive nodes
`(λ/2)` = 3.75 cm = 3.75 × 10−2 m, v = 1500 m/s
n = `v/λ`
As `λ/2` = 3.75 × 10−2 m
∴ λ = 7.5 × 10−2 m
From formula,
∴ n = `1500/(7.5xx10^-2)`
∴ n = 200 × 102
∴ n = 20 × 103
∴ n = 20 kHz
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