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A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s

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प्रश्न

A sound wave in a certain fluid medium is reflected at an obstacle to form a standing wave. The distance between two successive nodes is 3.75 cm. If the velocity of sound is 1500 m/s, find the frequency.

योग
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उत्तर

Distance between two successive nodes
`(λ/2)` = 3.75 cm = 3.75 × 10−2 m, v = 1500 m/s

n = `v/λ`

As `λ/2` = 3.75 × 10−2 m

∴ λ = 7.5 × 10−2 m

From formula, 

∴ n = `1500/(7.5xx10^-2)`

∴ n = 200 × 102

∴ n = 20 × 103

∴ n = 20 kHz

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अध्याय 6: Superposition of Waves - Exercises [पृष्ठ १५७]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 6 Superposition of Waves
Exercises | Q 11 | पृष्ठ १५७

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