Advertisements
Advertisements
Question
A solenoid of length π m and 5 cm in diameter has a winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its centre along the radius.
Advertisements
Solution
Given:
l = π m,
d = 5 cm,
N = 1000 turns,
i = 5 A
We know that,
μ0 = 4π × 10−7 Tm/A
To find: Magnetic field (B) = ?
Formulae:
- n = `N/l`
- B = μ0ni
Calculation:
From formula (i),
n = `1000/pi "turns"/"m"`
From formula (ii),
B = `4pi xx 10^-7 xx 1000/pi xx 5`
= `20 xx 10^{-7 + 3}`
= 2 × 10−3 T
The magnetic field is 2 × 10−3 T.
APPEARS IN
RELATED QUESTIONS
A solenoid of length π m and 5 cm in diameter has winding of 1000 turns and carries a current of 5 A. Calculate the magnetic field at its center along the axis.
A toroid of a central radius of 10 cm has windings of 1000 turns. For a magnetic field of 5 × 10-2 T along its central axis, what current is required to be passed through its windings?
What is Solenoid?
What is Toroid?
The length of solenoid is I whose windings are made of material of density D and resistivity p. The winding resistance is R. The inductance of solenoid is
[m = mass of winding wire, µ0 = permeability of free space]
A winding wire which is used to frame a solenoid can bear a maximum of 20 A current. If the length of the solenoid is 80 cm and its cross-sectional radius is 3 cm, then the required length of winding wire is ______ (B = 0.2 T)
The ratio of magnetic field and magnetic moment at the centre of a current carrying circular loop is x. When both the current and radius is doubled then the ratio will be ______.
Two current-carrying coils have radii r and 4r and have same magnetic induction at their centres. The ratio of voltage applied across them is ______.
Two toroids 1 and 2 have total number of turns 400 and 200 respectively with average radii 40 cm and 20 cm respectively. If they carry same current I, the ratio of the magnetic fields along the two loops is, ____________.
A 600 turn coil of effective area 0.05 m2 is kept perpendicular to a magnetic field 4 x 10-5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the e.m.f. induced in the coil will be: ____________.
A solenoid of 1.5 m length and 4 cm diameter possesses 20 turns per m. A current of 6 A is flowing through it. The magnetic induction at axis inside the solenoid is ____________.
A proton is projected with a uniform velocity 'v' along the axis of a current carrying solenoid, then ____________.
Magnetic induction due to a toroid does not depend upon ______.
A toroid is a long coil of wire wound over a circular core. If 'r' and 'R' are the radii of the coil and toroid respectively, the coefficient of self-induction of the toroid is (The magnetic field in it is uniform and R > > r) ____________.
(N = number of turns of the coil and µ0 = permeability of free space)
Magnetic field at the centre of a circular loop of area 'A' is 'B'. The magnetic moment of the loop will be (µ0 = permeability of free space) ____________.
A long solenoid carrying current 'I1' produces magnetic field 'B1' along its axis. If the current is reduced to 25% and number of turns per cm are increased four times, then new magnetic field 'B2' is ____________.
A charged particle carrying a charge 'q' and moving with velocity V, enters into a solenoid carrying a current T, along its axis. If 'B' is the magnetic induction along the axis of a solenoid, then the force 'F' acting on the charged particle will be ____________.
Obtain an expression for magnetic induction of a toroid of ‘N’ turns about an axis passing through its centre and perpendicular to its plane.
A conducting rod along the equator is 1 m long and carries a current of 15 A from east to west. The magnitude of Earth's magnetic field at the equator is `4/3 xx 10^(-4)` T. The magnitude and direction of the force on the rod are ______.
A current of 10 A passes through a coil having 5 turns and produces magnetic field at the centre of the coil having magnitude 0.5 x 10-4 T. Calculate diameter of the coil.
(µ0 = 4π x 10-7 Wb/Am)
