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Question
A soldering iron draws an energy of 43200 J in 4 min, when the current flowing through its element is 6 A, calculate the resistance of its heating element.
Numerical
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Solution
W = 43200 J; I = 6 A; t = 4 min = 240 s
\[W = I^{2} R t\]
\[R = \frac{W}{I^{2} t}\]
\[= \frac{43200}{(6)^{2} \times 240}\]
\[= \frac{43200}{36 \times 240}\]
\[= \frac{43200}{8640}\]
\[= 5.0 \text{ Ω}\]
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