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A Society Collected Rs 92.16. Each Member Collected as Many Paise as There Were Members. How Many Members Were There and How Much Did Each Contribute?

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Question

A society collected Rs 92.16. Each member collected as many paise as there were members. How many members were there and how much did each contribute? 

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Solution

Let M be the number of members.
Let r be the amount in paise donated by each member.
The total contribution can be expressed as follows:
M x r = Rs 92.16 = 9216 paise
Since the amount received as donation is the same as the number of members:

\[\therefore\] r = M 

Substituting this in the first equation, we get:
M x M = 9216
M2 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3
M2 = (2 x 2) x (2 x 2) x (2 x 2) x (2 x 2) x (2 x 2) x (3 x 3)
M = 2 x 2 x 2 x 2 x 2 x 3 = 96
To find r, we can use the relation r = M.
Let M be the number of members.
Let r be the amount in paise donated by each member.
The total contribution can be expressed as follows:
M x r = Rs 92.16 = 9216 paise
Since the amount received as donation is the same as the number of members:

\[\therefore\]r = 96
So, there are 96 members and each paid 96 paise.

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