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A Sector of a Circle of Radius 8cm Contains the Angle of 135°. Find the Area of Sector.

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Question

A sector of a circle of radius 8cm contains the angle of 135°. Find the area of sector.

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Solution

We know that the area A of a sector of an angle θ in the circle of radius r is given by  `A=theta/360^@xxpi r^2`

It is given that r = 8 cm and θ = 135°.

Now we substitute the value of r and θ in above formula,
`A=135^@/360^@xxpixx8xx8  cm^2`

`=24 pi  cm^2`

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