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Question
A’s present age is to B’s present age as 8 : 7. 27 years ago their ages were 5 : 4. Find their present ages.
Sum
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Solution
Let A’s present age = 8x
Let B’s present age = 7x
27 years ago:
A’s age = 8x − 27
B’s age = 7x − 27
`(8x - 27)/(7x - 27) = 5/4`
⇒ 4(8x − 27) = 5(7x − 27)
⇒ 32x − 108 = 35x − 135
⇒ 32x − 35x = −135 + 108
⇒ −3x = −27
⇒ x = 9
A’s present age = 8x
= 8 × 9
= 72
B’s present age = 7x
= 7 × 9
= 63
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