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A round table cover has six equal designs as shown in the given figure. If the radius of the cover is 35 cm, then find the total area of the design. [Use sqrt(3) = 1.732 and π = 3.14.]

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Question

A round table cover has six equal designs as shown in the given figure. If the radius of the cover is 35 cm, then find the total area of the design. [Use `sqrt(3) = 1.732` and π = 3.14.]

Sum
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Solution

Join each vertex of the hexagon to the centre of the circle.

The hexagon is made up of six triangles.

Total area of the design = Area of the  circle - Area of six triangles

`[22/7xx35xx35]-[6xx(sqrt(3)/4xx35xx35)]`

`=(35xx35)[22/7-((6xx1.732)/4)]`

`= 12225 (22/7-2.598)`

= 1225xx0.542

= 663.95 cm2

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Chapter 16: Area of Circle, Sector and Segment - EXERCISE 16A [Page 735]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 16 Area of Circle, Sector and Segment
EXERCISE 16A | Q 55. | Page 735
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