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Question
A room is 4.5 m long and 4 m wide. The floor of the room is to be covered with tiles of size 15 cm by 10 cm. Find the cost of covering the floor with tiles at the rate of ₹ 4.50 per tile.
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Solution
Given, length of room = 4.5 m, width of room = 4 m and size of tiles = 15 cm × 10 cm
∵ Area of room = l × b
= 4.5 × 4
= 18 m2
= 18 × (100)2 cm2 ...[∵ 1 m = 100 cm]
= 180000 cm2
∴ Area of 1 tile = 15 × 10 = 150 cm2
So, number of tiles = `"Area of room"/"Area of 1 tile" = 180000/150` = 1200
∴ Cost of covering the floor with tiles = ₹ 4.50 × 1200 = ₹ 5400
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