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A Right Angled Triangle Whose Sides Are 3 Cm, 4 Cm and 5 Cm is Revolved About the Sides Containing the Right Angle in Two Days. Find the Difference in Volumes of the Two Cones So Formed. Also, Find Their Curved Surfaces. - Mathematics

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Question

A right angled triangle whose sides are 3 cm, 4 cm and 5 cm is revolved about the sides containing the right angle in two days. Find the difference in columes of the two cones so formed. Also, find their curved surfaces.

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Solution

(i) Given that radius of cone(r1) = 4cm

Height of cone (h1) 3cm

Slant height of cone(l1) = 5cm

Volume of cone`(V_1)=1/3pir_1^2h_1`

`=1/3pi(4)^2(3)=16picm^3`

(ii) Given radius of second cone (r2) = 3cm

Height of cone(h2) = 4cm

Slant height of cone (l2) = 5cm

Volume of cone`(V_2)=1/3r_2^2h_2`

`=1/3pi(3)^2(4)=12picm^3`

Difference in volumes of two cones(V) = V1 - V2

V = 16π - 12π

V = 4πcm3

Curved surface area of first cone(S1) = πr1l1

S1 =π( 4)(5) = 20πcm2

Curved surface area of second cone(S2) = πr2l2

S2 = π(3)(5) = 15πcm2

S1 = 20πcmS2 = 15πcm2

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Chapter 14: Surface Areas and Volumes - Exercise 14.1 [Page 31]

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RD Sharma Mathematics [English] Class 10
Chapter 14 Surface Areas and Volumes
Exercise 14.1 | Q 59 | Page 31
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