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Question
A resistance of 20 ohms has a current of 2 amperes flowing in it. What potential difference is there between its ends?
Numerical
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Solution
Here:
Resistance, R = 20 Ω
Current, I = 2 A
Substituting these values in the Ohm's equation, V/I = R:
Potential difference, V = I x R = 2 x 20 = 40 V
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