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Question
A rectangular tank is 80 m long and 25 m broad. Water flows into it through a pipe whose cross-section is 25 cm2, at the rate of 16 km per hour. How much the level of the water rises in the tank in 45 minutes.
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Solution
Let the level of water be risen by h cm.
Then,
Volume of water in the tank = `8000xx2500xxhcm^2`
Area of cross – section of the pipe =`25cm^2`
Water coming out of the pipe forms a cuboid of base area `25cm^2` and length equal to the distance travelled in 45 minutes with the speed 16km/hour.
i.e., length=`16000xx100xx45/60cm`
∴Volume of water coming out of pipe in 45 minutes
`=25xx16000xx100(45/60)`
Now, volume of water in the tank = volume of water coming out of the pipe in 45 minutes
`⇒8000xx2500xxh=16000xx100xx45/60xx25`
`⇒h=(16000xx100xx45xx25)/(8000xx2500xx60)cm=1.5cm.`
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