English

A radioactive nucleus XZAX2Z2AX undergoes spontaneous decay in the sequence XZAX2Z2AX⟶XZ−1X2Z−12B⟶XZ−3X2Z−32C⟶XZ−2X2Z−22D, where Z is the atomic number of element X. The possible decay

Advertisements
Advertisements

Question

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX->_{Z-1}B->_{Z-3}C->_{Z-2}D}\], where Z is the atomic number of element X. The possible decay particles in the sequence are ______

Options

  • β+, α, β-

  • β-, α, β+

  • α, β-, β+

  • α, β+, β-

MCQ
Fill in the Blanks
Advertisements

Solution

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX->_{Z-1}B->_{Z-3}C->_{Z-2}D}\], where Z is the atomic number of element X. The possible decay particles in the sequence are β+, α, β-.

shaalaa.com
Radioactive Decay Law
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×