हिंदी

A radioactive nucleus XZAX2Z2AX undergoes spontaneous decay in the sequence XZAX2Z2AX⟶XZ−1X2Z−12B⟶XZ−3X2Z−32C⟶XZ−2X2Z−22D, where Z is the atomic number of element X. The possible decay

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प्रश्न

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX->_{Z-1}B->_{Z-3}C->_{Z-2}D}\], where Z is the atomic number of element X. The possible decay particles in the sequence are ______

विकल्प

  • β+, α, β-

  • β-, α, β+

  • α, β-, β+

  • α, β+, β-

MCQ
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उत्तर

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX->_{Z-1}B->_{Z-3}C->_{Z-2}D}\], where Z is the atomic number of element X. The possible decay particles in the sequence are β+, α, β-.

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Radioactive Decay Law
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