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A radioactive nucleus AZAA2Z2AX undergoes spontaneous decay in the sequence AZAA2Z2AX⟶AZ−1A2Z−12B⟶AZ−3A2Z−32C⟶AZ−2A2Z−22D where Z is

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Question

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX -> _{Z-1 }B -> _{Z-3}C -> _{Z-2}D }\] where Z is the atomic number of element X. The possible decay particles in the sequence are ______.

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  • β+, α, β−  

  • β, α, β

  • α, β, β

  • α, β+, β− 

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Solution

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX -> _{Z-1 }B -> _{Z-3}C -> _{Z-2}D }\] where Z is the atomic number of element X. The possible decay particles in the sequence are β+, α, β  

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Radioactive Decay Law
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