हिंदी

A radioactive nucleus AZAA2Z2AX undergoes spontaneous decay in the sequence AZAA2Z2AX⟶AZ−1A2Z−12B⟶AZ−3A2Z−32C⟶AZ−2A2Z−22D where Z is

Advertisements
Advertisements

प्रश्न

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX -> _{Z-1 }B -> _{Z-3}C -> _{Z-2}D }\] where Z is the atomic number of element X. The possible decay particles in the sequence are ______.

विकल्प

  • β+, α, β−  

  • β, α, β

  • α, β, β

  • α, β+, β− 

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

A radioactive nucleus \[\ce{^A_ZX}\] undergoes spontaneous decay in the sequence \[\ce{^A_ZX -> _{Z-1 }B -> _{Z-3}C -> _{Z-2}D }\] where Z is the atomic number of element X. The possible decay particles in the sequence are β+, α, β  

shaalaa.com
Radioactive Decay Law
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×