Question

A power house generates 200 MW of power. If the generating e.m.f. 40,000 V, what is the magnitude of current produced?

Answer 1

Given: 

Power generated (\(P\)) = \(200\text{ MW} = 200 \times 10^6\text{ W} = 200,000,000\text{ W}\)

Generating e.m.f. (\(V\)) = \(40,000\text{ V}\)

Formula:

Electric Power (P) is the product of voltage (V) and current (I):

\(P=V\times I\)

\[I=\frac{P}{V}\]

\[=\frac{200,000,000}{40,000}\]

\[=\frac{20,000}{4}\]

\(I={5,000}\text{\ A}\)

The magnitude of the current produced by the power house is 5,000 A (or 5 kA).