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A plane left 30 minutes later than the schedule time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hr from its usual speed. Find its usual speed.

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Question

A plane left 30 minutes later than the schedule time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/hr from its usual speed. Find its usual speed.

Sum
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Solution

Let the usual speed of plane be x km/hr

Total distance = 1500 km

From the given information, we have

`1500/x - 1500/(x + 250) = 30/60 = 1/2`

`(1500x + 1500 xx 250 - 1500x)/(x(x + 250)) = 1/2`

`(375000)/(x^2 + 250x) = 1/2`

x2 + 250x = 750000

x2 + 250x – 750000 = 0

x2 + 1000x – 750x – 750000 = 0

x(x + 1000) – 750(x + 1000) = 0

(x + 1000)(x – 750) = 0

x = –1000, 750

Since, speed cannot be negative.

So, x = 750.

Hence, the usual speed of plane is 750 km/hr.

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Chapter 6: Solving (simple) Problems (Based on Quadratic Equations) - Exercise 6 (E) [Page 79]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (E) | Q 6. | Page 79
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