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Question
A picture is painted on a ceiling of a marriage hall whose length and breadth are 18 m and 7 m respectively. There is a border of 10 cm along each of its sides. Find the area of the border
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Solution
Length of the ceiling L = 18 m
Breadth of the ceiling B = 7 m
Area of the ceiling = L × B sq.units
= 18 × 7 m2
= 126 m2
Width of the boarder W = 10 cm
= `10/100` m
= 0.1 m
Length of the ceiling without border = L – 2W
= 18 – 2(0.1) m
= 18 – 0.2 m
= 17.8 m
Breadth of the ceiling without border = B – 2W
= 7 – 2(0.1) m
= 7 – 0.2 m
= 6.8 m
Area of the ceiling without border = l × b sq.units
= 17.8 × 6.8 m2
= 121.04 m2
∴ Area of the border = Area of the ceiling – Area of the ceiling without border
= 126 – 121.04 m2
= 4.96 m2
Area of the border = 4.96 m2
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