Question

A person starts a job with a fixed salary and yearly increment. After 4 years his salary is ₹ 15000 and after 10 years it becomes ₹ 18000. Then find his monthly salary and increment.

Answer 1

Let the fixed salary be ₹ x and the annual increment be ₹ y.

Then, salary after 4 years = x + 4y

salary after 10 years = x + 10y

According to the first condition,

After 4 years his salary is ₹ 15,000.

∴ x + 4y = 15000   ...(i)

According to the second condition,

After 10 years his salary is ₹ 18,000.

∴ x + 10y = 18000   ...(ii)

Subtracting equation (i) from (ii), we get
   x + 10y = 18000
– x +   4y = 15000 
    −     −        −       
           6y = 3000

∴ y = `3000/6`

∴ y = 500

Substituting y = 500 in equation (i), we get

x + 4(500) = 15000

∴ x + 2000 = 15000

∴ x = 13000

∴ The monthly salary is ₹ 13,000 and yearly increment is ₹ 500.