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A person rowing at the rate of 5 km/h in still water, takes thrice as much time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream.

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Question

A person rowing at the rate of 5 km/h in still water, takes thrice as much time in going 40 km upstream as in going 40 km downstream. Find the speed of the stream.

Sum
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Solution

Let the speed of the stream be v km/h

Given that, speed of a person rowing in still water = 5 km/h

The speed of a person rowing in downstream = (5 + v) km/h

And the speed of a person has rowing in upstream = (5 – v) km/h

Now, the person takes time to cover 40 km downstream,

t1 = `40/(5 + v)` hours   ...`[because "speed" = "distance"/"time"]`

Now, the person takes time to cover 40 km upstream,

t2 = `40/(5 - v)` hours

By condition,

t2 = t1 × 3

⇒ `40/(5 - v) = 40/(5 + v) xx 3`

⇒ `1/(5 - v) = 3/(5 + v)`

⇒ 5 + v = 15 – 3v

⇒ 4v = 10

∴ v = `10/4` = 2.5 km/h

Hence, the speed of the stream is 2.5 km/h.

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Chapter 3: Pair of Liner Equation in Two Variable - Exercise 3.4 [Page 34]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 10
Chapter 3 Pair of Liner Equation in Two Variable
Exercise 3.4 | Q 7 | Page 34
R.D. Sharma Mathematics [English] Class 10
Chapter 3 Pair of Linear Equations in Two Variables
EXERCISE 3.10 | Q 3. | Page 3.66

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