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Question
A number is chosen at random from the number –3, –2, –1, 0, 1, 2, 3. What will be the probability that square of this number is less then or equal to 1?
Sum
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Solution
S = {−3, −2, −1, 0, 1, 2, 3}
Let E be the event of getting a number whose square is less than or equal to 1.
So, E = {−1, 1, 0}
\[P\left( E \right) = \frac{3}{7}\]
Hence, the probability of getting a number whose square is less than or equal to is \[\frac{3}{7}\]
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