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Question
A motorcyclist performs stunt along the cylindrical wall of a ‘Well of Death’ of inner radius 4 m. Coefficient of static friction between tyres and the wall is 0.4. Calculate the maximum period of revolution. (Use g = 10 m/s2)
Numerical
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Solution
Given: Radius (r) = 4 m
Coefficient of static friction (µ) = 0.4
g = 10 m/s2
To find: Maximum period (Tmax) = ?
Formula: `T_(max) = (2 pi r)/(v_min)`
Let us find vmin
∴ `v_(min) = sqrt((rg)/µ)`
∴ `v_(min) = sqrt((4 xx 10)/(0.4))`
∴ `v_(min) = sqrt((4 xx 10)/(4 xx 10^(-1)))`
∴ `v_(min) = sqrt(100)`
∴ vmin = 10 m/s
∴ `T_(max) = (2 pi r)/(v_min)`
= `(2 xx 3.142 xx 4)/(10)`
= 8 × 0.3142
= 2.5136 s
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