Question

A month is selected at random in a year. The probability that it is March or October, is

Options

• \[\frac{1}{12}\]

• \[\frac{1}{6}\]

• \[\frac{3}{4}\]

•  None of these

Answer 1

A month is selected at random in a year.

TO FIND: Probability that it is March or October

Total months in a year is 12

Hence total number of favorable outcome is 2 i.e. March or October

`"We know that PROBABILITY" =" Number of favourable event"/"Total number of event"` 

Hence probability that the month selected is March or October is equal to  `2/12=1/6`