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A Metal M, Forms a Volatile Chloride Containing 65.5% Chlorine. If the Density of the Chloride Relative to Hydrogen is 162.5, Find the Molecular Formula of the Chloride.

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Question

A metal M, forms a volatile chloride containing 65.5% Chlorine. If the density of the chloride relative to hydrogen is 162.5, find the molecular formula of the chloride. [M = 56, Cl = 35.5]

Short/Brief Note
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Solution

Given, density of chloride relative to hydrogen = 162.5
Percentage of chlorine = 65.5‰
Percentage of Metal M = 100 - 65.5 = 34.5‰

Element Atomic mass Percentage Relative  number of moles Simplest mole ratio Whole number ratio
M 56 34.5 34.5/56 = 0.62 0.62/0.62 = 1 1
Cl 35.5 65.5 65.5/35.5 =1.85 1.85/0.62 = 2.98 3

Empirical formula = MCl3
Empirical formula mass = 56 + 3 x 35.5 = 162.5
Molecular mass = 2 x Vapour density = 2 x 162.5 = 325
n = Molecular mass / Empirical formula mass
= 325/162.5 = 2
Molecular formula = n x empirical formula
= 2 X MCl= M2Cl6

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Chapter 5: Mole Concept and Stoichiometry - Exercise 5 [Page 119]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Exercise 5 | Q 7 | Page 119

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