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Question
A man walks a distance of 5 km in 2 hours. Then he goes in a bus to a nearby town, which is 40 km, in further 2 hours. From there, he goes to his office in an autorickshaw, a distance of 5 km, in `1/2` hour. What was his average speed during the whole journey?
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Solution
Distance of 5 km travelled on foot in 2 hours
Distance of 40 km travelled by bus in 2 hours
Distance of 5 km travelled by Rickshaw in `1/2` hour
Total distance covered = 5 + 40 + 5 = 50 km
Time taken = `2+2+1/2=4 1/2=9/2` hours
∴ Average speed = `"Distance"/"Time"`
= `50/(9/2)`
= `(50xx2)/9`
= `100/9` km/h
= `11 1/9` km/h
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