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Question
A man borrowed Rs.16,000 for 3 years under the following terms:
20% simple interest for the first 2 years.
20% C.I. for the remaining one year on the amount due after 2 years, the interest being compounded half-yearly.
Find the total amount to be paid at the end of the three years.
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Solution
For the first 2 years
S.I. = `[ "P" xx "N" xx "R"]/100`
⇒ S.I. = `[ 16,000 xx 2 xx 20 ]/100` ⇒ S.I. = 6,400
Amount = S.I. + P
⇒ Amount = 6,400 + 16,000 = Rs. 22,400
Amount in the account at the end of the two years is Rs.22,400.
For the remaining one year
A = `P( 1 + r/[ 2 xx 100 ])^( n xx 2)`
⇒ A = `22,400( 1 + 20/200 )^2`
⇒ A = `22,400( 11/10 )^2`
⇒ A = 27,104
The total amount to be paid at the end of the three years is Rs. 27,104.
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