Advertisements
Advertisements
Question
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
How do rates of evaporation and condensation change initially?
Advertisements
Solution
Since the temperature is constant, the rate of evaporation also remains constant. When the volume of the container is increased, the density of the vapour phase decreases. As a result, the rate of collisions of the vapour particles also decreases. Hence, the rate of condensation decreases initially.
APPEARS IN
RELATED QUESTIONS
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
What is the initial effect of the change on vapour pressure?
A liquid is in equilibrium with its vapour in a sealed container at a fixed temperature. The volume of the container is suddenly increased.
What happens when equilibrium is restored finally and what will be the final vapour pressure?
At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms
\[\ce{I2(g) <=> 2I(g)}\]
Calculate Kpfor the equilibrium.
Explain why pure liquids and solids can be ignored while writing the equilibrium constant expression?
At a particular temperature and atmospheric pressure, the solid and liquid phases of a pure substance can exist in equilibrium. Which of the following term defines this temperature?
(i) Normal melting point
(ii) Equilibrium temperature
(iii) Boiling point
(iv) Freezing point
Match the following equilibria with the corresponding condition:
| Column I | Column II |
| (i) Liquid ⇌ Vapour | (a) Saturated solution |
| (ii) Solid ⇌ Liquid | (b) Boiling point |
| (iii) Solid ⇌ Vapour | (c) Sublimation point |
| (iv) Solute (s) ⇌ Solute (solution) | (d) Melting point Unsaturated solution |
