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Karnataka Board PUCPUC Science Class 11

A Light Ray is Incident Normally on the Face Ab of a Right-angled Prism Abc (μ = 1.50) as Shown in Figure.

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Question

A light ray is incident normally on the face AB of a right-angled prism ABC (μ = 1.50) as shown in figure. What is the largest angle ϕ for which the light ray is totally reflected at the surface AC?

Sum
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Solution

Given,
Refractive index (μ) of prism = 1.50
Let us take θc as the critical angle for the glass.

So, According to Snell's law,
\[\frac{\sin  \theta_c}{\sin  90^\circ } = \frac{1}{\mu}\]
\[\Rightarrow \sin \theta c = \frac{1}{1 . 5} = \frac{2}{3}\]
\[\Rightarrow    \theta_c  =  \sin^{- 1} \frac{2}{3}\]
Condition for total internal reflection: 90° − \[\phi\] θ
⇒ \[\phi\] < 90°  - θc 
\[\Rightarrow    \theta_c  =  \sin^{- 1} \frac{2}{3}\] 
\[\Rightarrow \phi < \cos^{- 1} \left( \frac{2}{3} \right)\]

Hence, the largest angle for which light is totally reflected at the surface AC is \[\cos^{- 1} \left( \frac{2}{3} \right)\]

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Chapter 18: Geometrical Optics - Exercise [Page 414]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 18 Geometrical Optics
Exercise | Q 27 | Page 414
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