Question

A letter of English alphabets is chosen at random. Determine the probability that the letter is a consonant.

Answer 1

We know that, in english alphabets, there are (5 vowels + 21 consonants) = 26 letters.

So, total number of outcomes in english alphabets are, n(S) = 26

Let E = Event of choosing a english alphabet, which is a consonant

= {b, c, d, f, g, h, j, k, l, m, n, p, q, r, s t, v, w, x, y, z}

∴ n(E) = 21

Hence, required probability = `(n(E))/(n(S)) = 21/26`