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A lens which forms a real image has a focal length 8 cm. Calculate its power.

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Question

A lens which forms a real image has a focal length 8 cm. Calculate its power.

Numerical
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Solution

The lens forms a real image, therefore it is a convex lens.

Focal length of the lens (f) = +8 cm [f for convex lens is +ive]

\[ \text{Applying, } \mathrm{P} = \frac{100}{f \text{(in cm)}} \]

\[ \Rightarrow \mathrm{P} = \frac{100}{8} \]

\[ \Rightarrow \mathrm{P} = + \ 12.5 \ \text{D} \]

Thus, power is +12.5 D. The positive sign shows that lens is convex.

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Chapter 4: Refraction of Light - NUMERICAL PROBLEMS ON LENSES [Page 98]

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Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 10
Chapter 4 Refraction of Light
NUMERICAL PROBLEMS ON LENSES | Q 2. | Page 98
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