Question

A kite is flying at a height of 75 m from the level ground, attached to a string inclined at 60° to the horizontal. Find the length of the string, assuming that there is no slack in it. [Take `sqrt(3) = 1.732`.]

Answer 1

Let OX be the horizontal ground and A be the position of the kite.
Also, let O be the position of the observer and OA be the thread.
Now, draw AB ⊥ OX.
We have:
∠BOA= 60°,OA= 75m and ∠OBA = 90°
Height of the kite from the ground = AB = 75 m
Length of the string OA =  xm

In the right ΔOBA,we have:
`(AB)/(OA ) = sin 60° = sqrt(3)/2`
`⇒ 75/x = sqrt(3)/2`

`⇒  x = (75xx2)/sqrt(3) = 150/1.732 = 86.6m`
Hence, the length of the string is 86.6m