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Question
If A and B be mutually exclusive events associated with a random experiment such that P(A) = 0.4 and P(B) = 0.5, then find
P ( \[\bar{ A} \] ∩ B)
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Solution
Given:
P(A) = 0.4 and P(B) = 0.5
If A and B be mutually exclusive event, then P (A ∩ B) = 0
\[P\left( \bar{A} \cap B \right) = P\left( B \right) - P\left( A \cap B \right)\]
= 0.5 - 0 = 0.5
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