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A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block

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Question

A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is ______.

Options

  • 6 N

  • 10 N

  • zero

  • 4 N

MCQ
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Solution

A horizontal force 10 N is applied to a block A as shown in figure. The mass of blocks A and B are 2 kg and 3 kg, respectively. The blocks slide over a frictionless surface. The force exerted by block A on block B is 6 N.

Explanation:

Given: Total mass (M) = 2 kg + 3 kg = 5 kg

Applied force (F) = 10 N

Using Newton’s second law:

a = F/M

= 10/5

= 2 m/s2

The force exerted by block A on block B (FAB) is the only horizontal force causing block B to accelerate. Applying Newton's second law specifically to block B:

FAB = mB × a

= 3 × 2

= 6 N

∴ The force exerted by block A on block B is 6 N.

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